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  1. java語言

    Java鍵盤輸入實例

    時間:2025-05-23 20:38:45 java語言 我要投稿
    • 相關推薦

    Java鍵盤輸入實例

      引導語:java不像C中擁有scanf這樣功能強大的函數,大多是通過定義輸入輸出流對象,以下是百分網小編分享給大家的Java鍵盤輸入實例,歡迎閱讀!

    Java鍵盤輸入實例

      import java.util.Scanner;

      /**

      * 測試從鍵盤讀取用戶的輸入,關鍵類為Scanner

      * @author Administrator

      *

      */

      public class TestInput {

      public static void main(String[] args) {

      Scanner s = new Scanner(System.in);

      System.out.println("請輸入你的姓名:");

      String name = s.nextLine();

      System.out.println("請輸入你的年齡:");

      int age = s.nextInt();

      System.out.println("請輸入你的工資:");

      float salary = s.nextFloat();

      System.out.println("你的信息如下:");

      System.out.println("姓名:"+name+"\n"+"年齡:"+age+"\n"+"工資:"+salary);

      }

      }

      說明:Scanner的對象的方法nextLine()接收字符和字符串類型的輸入;nextInt()接收int類型的;nextFloat()接收float類型的,相信后面的就不用一一列舉了吧。

      方法2:

      BufferedReader reader=new BufferedReader(new InputStreamReader(System.in));

      System.out.print("Please input a number:");

      String str=reader.readLine(); //獲取字符串

      System.out.println("The number you input is:"+str);

      或

      InputStreamReader reader = new InputStreamReader(System.in);

      BufferedReader input = new BufferedReader(reader);

      System.out.print("Enter your age: ");

      String text = input.readLine();

      int age = new Integer(text).intValue();

      System.out.println("You are " + age + " years old, now,");

      int year = 2003 - age;

      System.out.println("so you were probably born in " + year);

      需要拋出io異常。

      import java.io.*;

      - @5 n0 _4 H: c( y: Hclass JavaIO_02N {' U- \9 P1 S, C2 m- R3 p& t

      public static void main(String param[])

      # u P+ ]+ a2 L6 O! V {: B7 A6 r3 ^ [4 ~

      String nn1="";//定義一個String整型對象nn1: b5 T) n6 E9 f4 @9 p

      BufferedReader distream = new BufferedReader(new InputStreamReader(System.in));

      , p1 J D/ B, @1 L" q6 P' a System.out.println("鍵入一個整數"); r& m/ H2 s' Q h" T( |+ j

      nn1=distream.readLine();//進行輸入,并把輸入的數存入nn1中/ l, u4 y3 e5 R \

      ) J+ D7 n$ u; z% v3 Z7 g# S* w0 l int n1=Integer.parseInt(nn1);( z4 l# |( L/ q

      if(n1%2==0)

      . C6 b9 U$ D* F( y! K System.out.println(n1+"是一個偶數");

      3 ?! ^" c% C9 ], i- G9 L9 }/ b else( u- G, Z( Z* { V# _; _0 O

      System.out.println(n1+"是一個奇數"); 2 _; b) N, Q2 \4 W9 D: y$ t! E5 ~# J

      }% c! z' y( d6 d/ v# {. _7 Q

      }

      1 F: w6 M1 H) |8 j) O: e' C4 e

      & v" }5 S9 }& Y& l8 B

      " f9 G8 K, H+ A6 P% ajava不可能出現語句在任何方法,類之外的

      /* * Created on 2005-4-5

      * * TODO To change the template for this generated file go to

      * Window - Preferences - Java - Code Style - Code Templates

      */

      import java.io.BufferedReader;

      import java.io.IOException;

      import java.io.InputStreamReader;

      /**

      * @author Zhangql

      *

      * TODO To change the template for this generated type comment go to

      * Window - Preferences - Java - Code Style - Code Templates

      */

      public class EnterConsole

      {

      public static void main(String[] args) throws IOException

      {

      EnterConsole enterConsole = new EnterConsole();

      enterConsole.printConsoleChar();

      }

      /**

      * 從控制對接收一行字符串,然后輸出到控制臺

      * @throws IOException

      */

      public void printConsoleLine() throws IOException

      {

      BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

      String str = null;

      System.out.println("Enter your value:");

      str = br.readLine();

      System.out.println("your value is :"+str);

      }

      /**

      * 從控制臺接收一個字符

      * 然后打印到控制臺上

      * @throws IOException

      */

      public void printConsoleChar() throws IOException

      {

      System.out.print("Enter a Char:");

      char i = (char) System.in.read();

      System.out.println("your char is :"+i);

      }

      }

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